2t^=9+t^2

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Solution for 2t^=9+t^2 equation: 



2t^=9+t^2

We move all terms to the left:

2t^-(9+t^2)=0

We add all the numbers together, and all the variables

-(9+t^2)+2t=0

We get rid of parentheses

-t^2+2t-9=0

We add all the numbers together, and all the variables

-1t^2+2t-9=0

a = -1; b = 2; c = -9;
Δ = b2-4ac
Δ = 22-4·(-1)·(-9)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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